How do you solve $(x+1)/3 = (x-1)/4$ ?

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Answer 1 · 2016-06-05T06:12:06

x=-7

4(x+1)=3(x-1)
4x+4=3x-3
4x-3x=-4-3
x=-7

Answer 2 · 2016-06-05T06:14:59

$x=-7$

In the equation $(x+1)/3=(x-1)/4$ , let us first multiply both sides by LCD of $3$ and $4$ i.e. $12$ to eliminate fractions.

Hence this equation can be written as

$(x+1)/3xx12=(x-1)/4xx12$

$4(x+1)=3(x-1)$ or

$4x+4=3x-3$

now transposing terms containing variable $x$ to left hand side and constant terms to right hand side, we get

$4x-3x=-3-4$ or

$x=-7$

How do you solve (x+1)/3 = (x-1)/4(x+1)/3 = (x-1)/4?