How do you solve $(x-2)/2-(x+2)/4=(1/2)$ ?

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Answer 1 · 2016-03-28T19:34:35

$x=8$

Write as $" " (2(x-2))/4-(x+2)/4=2/4$

Multiply everything by 4 giving:

$2(x-2)-(x+2)=2$

$2x-4-x-2=2$

$x-6=2$

Add 6 to both sides

$x=8$
'~~~~~~~~~~~~~~~~~~~~~~~~~~~
Check
$(8-2)/2-(8+2)/4=?$

$6/2 -5/2=?$

Left hand side = right hand side $= 1/2" "$ confirmed!

How do you solve (x-2)/2-(x+2)/4=(1/2)(x-2)/2-(x+2)/4=(1/2)?