How do you solve $x^(2/3)+15=24$ ?

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Answer 1 · 2016-12-09T00:19:43

$x=+-27$

Given:

$x^(2/3)+15 = 24$

Subtract $15$ from both sides to get:

$x^(2/3) = 9$

Cube both sides to get:

$x^2 = 729$

Take the square root of both sides, allowing for both positive and negative square roots to get:

$x = +-27$

Assuming that we are dealing purely with Real numbers, both of these solutions are solutions of the original equation.

How do you solve x^(2/3)+15=24x^(2/3)+15=24?