How do you solve $x^2 + 3 = –4x$ using the quadratic formula?

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Answer 1 · 2016-04-04T23:55:58

First you put everything to one side, by adding $4x$

$->x^2+4x+3=0$

Quadratic formula: $x_(1,2)=(-b+-sqrt(b^2-4ac))/(2a)$

Or:
$x_(1,2)=(-4+-sqrt(4^2-4*1*3))/(2*1)$

$x_(1,2)=(-4+-2)/2->x_1=-1,x_2=-3$

Extra:
Factoring would have been easier here:
$(x+1)(x+3)=0$ , with the same result.

How do you solve x^2 + 3 = –4xx^2 + 3 = –4x using the quadratic formula?