How do you solve $x^ (-2/3) = 9$ ?

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Answer 1 · 2017-10-23T00:48:17

Please see below.

Write it as $1/((root(3)x)^2) = 9$

So $1/9 = (root(3)x)^2$

$root(3)x = +- sqrt(1/9) = +- 1/3$

$x = (+-1/3)^3 = +- 1/27$

How do you solve x^ (-2/3) = 9x^ (-2/3) = 9?