Question

How do you solve `(x^2 - 5)/(x + 3) = 0`?

Answer 1

I found: `x=+-sqrt(5)`

Explanation:

We need to find the value(s) of `x` that satisfy our equation; we also need to avoid `x` values that make our relationship INDETERMINATE!
This is because if you make the denominator zero (choosing `x=-3`) the division by zero is not possible!
So as first consideration we say that:
`x!=-3`
Next we solve our equation:

`x^2-5=0*(x+3)`
moving the denominator to the right of the equal sign;
so:
`x^2-5=0`
`x^2=5`
`x=+-sqrt(5)`