How do you solve $x^2 - 6x + 2 = 0$ using the quadratic formula?

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Answer 1 · 2016-03-10T12:44:12

$x=3+-sqrt7$

$color(blue)(x^2-6x+2=0$

This is a Quadratic equation (in form $ax^2+bx+c$ )

$color(brown)(x=(-b+-sqrt (b^2-4ac))/(2a)$

Where

$color(red)(a=1,b=-6,c=2$

Substitute the values in the formula

$rarrx=(-(-6)+-sqrt(-6^2-4(1)(2)))/(2(1))$

$rarrx=(6+-sqrt(36-8))/(2)$

$rarrx=(6+-sqrt(28))/2$

$rarrx=(6+-sqrt(4*7))/2$

$rarrx=(6+-2sqrt(7))/2$

$rarrx=(cancel6+-cancel2sqrt(7))/cancel2$

$rArrcolor(green)(x=3+-sqrt7$

How do you solve x^2 - 6x + 2 = 0x^2 - 6x + 2 = 0 using the quadratic formula?