How do you solve $(x^2 - 7)/(x - 4) = 0$ ?

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Answer 1 · 2016-04-08T05:04:43

$x=sqrt7$

$color(blue)((x^2-7)/(x-4)=0$

Multiply both sides by $x-4$

$rarr(x^2-7)/cancel(x-4)*cancel(x-4)=0*x-4$

$rarrx^2-7=0$

Add $7$ both sides

$rarrx^2-7+7=0+7$

$rarrx^2=7$

Take the square root of both sides

$rarrsqrt(x^2)=sqrt7$

$color(green)(rArrx=sqrt7$

How do you solve (x^2 - 7)/(x - 4) = 0(x^2 - 7)/(x - 4) = 0?