How do you solve $x^{2} = 7 x + 11$ $x^2 = 7x + 11$ using the quadratic formula?

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Answer 1 · 2018-06-09T08:20:04

$x = \frac{7 + \sqrt{93}}{2}, \frac{7 - \sqrt{93}}{2}$ $color(green)(x = (7 + sqrt(93)) / 2, (7 - sqrt(93)) / 2$

$x^{2} = 7 x + 11$ $x^2 = 7x + 11$

$Quadratic Formula x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$ $color(crimson)("Quadratic Formula " x = (-b +- sqrt(b^2 - 4ac)) / (2a)$

$a = 1, b = - 7, c = - 11$ $a = 1, b = -7, c = -11$

$x = 7 \pm \sqrt{7^{2} + 44} \frac{)}{2}$ $x = 7 +- sqrt(7^2 + 44)) / 2$

$x = \frac{7 + \sqrt{93}}{2}, \frac{7 - \sqrt{93}}{2}$ $color(green)(x = (7 + sqrt(93)) / 2, (7 - sqrt(93)) / 2$

How do you solve x^2 = 7x + 11x2=7x+11x^2 = 7x + 11 using the quadratic formula?