How do you solve $x^{2} + 8 x = 24$ $x^2 + 8x = 24$ using the quadratic formula?

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Answer 1 · 2016-09-11T13:37:37

$x = - 4 \pm 2 \sqrt{10}$ $x = - 4 pm 2 sqrt(10)$

We have: $x^{2} + 8 x = 24$ $x^(2) + 8 x = 24$

First, let's subtract $24$ $24$ from both sides of the equation:

$\Rightarrow x^{2} + 8 x - 24 = 0$ $=> x^(2) + 8 x - 24 = 0$

Then, let's apply the quadratic formula:

$\Rightarrow x = \frac{- 8 \pm \sqrt{8^{2} - 4 (1) (- 24)}}{2 (1)}$ $=> x = (- 8 pm sqrt(8^(2) - 4 (1) (- 24))) / (2 (1))$

$\Rightarrow x = \frac{- 8 \pm \sqrt{64 + 96}}{2}$ $=> x = (- 8 pm sqrt(64 + 96)) / (2)$

$\Rightarrow x = \frac{- 8 \pm \sqrt{160}}{2}$ $=> x = (- 8 pm sqrt(160)) / (2)$

$\Rightarrow x = \frac{- 8 \pm 4 \sqrt{10}}{2}$ $=> x = (- 8 pm 4 sqrt(10)) / (2)$

$\Rightarrow x = - 4 \pm 2 \sqrt{10}$ $=> x = - 4 pm 2 sqrt(10)$

Therefore, the solutions to the equation are $x = - 4 - 2 \sqrt{10}$ $x = - 4 - 2 sqrt(10)$ and $x = - 4 + 2 \sqrt{10}$ $x = - 4 + 2 sqrt(10)$ .

How do you solve x^2 + 8x = 24x2+8x=24x^2 + 8x = 24 using the quadratic formula?