How do you solve $x^2=-x+7$ using the quadratic formula?

Question

2414 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-25T20:05:21

The roots are $2.192582404$ and $-3.192582404$

Re-arrange the equation into a standard form
$ax^2+bx+c=0$

in this case, that would be

1) $x^2+x-7=0$

Using the quadratic formula $(-b +-sqrt(b^2-4ac))/(2a)$

Substituting the values from equation into the general formula

$(-1 +-sqrt(1^2-4*1*-7))/(2*1)$

simplifies to
$(-1 +-sqrt(29))/(2)$

or $2.192582404$ and $-3.192582404$

How do you solve x^2=-x+7x^2=-x+7 using the quadratic formula?