How do you solve $\frac{x - 3}{3} + \frac{x - 3}{4} = \frac{7}{24}$ $(x-3)/3+(x-3)/4=7/24$ ?

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How do you solve $\frac{x - 3}{3} + \frac{x - 3}{4} = \frac{7}{24}$ $(x-3)/3+(x-3)/4=7/24$ ?

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Answer 1 · 2017-10-17T01:39:40

$x = \frac{7}{2}$ $x=7/2$

Explanation:

Given -

$\frac{x - 3}{3} + \frac{x - 3}{4} = \frac{7}{24}$ $(x-3)/3+(x-3)/4=7/24$

Multiply both sides by 24

$(\frac{x - 3}{3}) \times 24 + (\frac{x - 3}{4}) \times 24 = \frac{7}{24} \times 24$ $((x-3)/3)xx24+((x-3)/4)xx24=7/24xx24$

$(x - 3) 8 + (x - 3) 6 = 7$ $(x-3)8+(x-3)6=7$

$8 x - 24 + 6 x - 18 = 7$ $8x-24+6x-18=7$

$14 x - 42 = 7$ $14x-42=7$

$14 x = 7 + 42 = 49$ $14x=7+42=49$

$x = \frac{49}{14} = \frac{7}{2}$ $x=49/14=7/2$

$x = \frac{7}{2}$ $x=7/2$

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How do you solve $\frac{x - 3}{3} + \frac{x - 3}{4} = \frac{7}{24}$ $(x-3)/3+(x-3)/4=7/24$ ?

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Explanation:

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How do you solve (x-3)/3+(x-3)/4=7/24x−33+x−34=724(x-3)/3+(x-3)/4=7/24?

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How do you solve $\frac{x - 3}{3} + \frac{x - 3}{4} = \frac{7}{24}$ $(x-3)/3+(x-3)/4=7/24$ ?