How do you solve $x/3-7 =6-(3x)/4$ ?

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Answer 1 · 2015-05-28T16:59:30

Given $x/3-7 = 6 -3x/4$

Since I'm lazy and not a big fan of working with fractions when I don't have to,
I'd start by multiplying everything by $12$ to get

$4x -84 = 72 - 9x$

Moving the $x$ 's to one side and the pure numerics to to the other:
$13x = 156$

$x = 12$

How do you solve x/3-7 =6-(3x)/4x/3-7 =6-(3x)/4?