How do you solve $x+3y=11$ and $x+4y=14$ ?

Question

3912 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-08-02T14:04:57

The solution for the system of equations is
$color(green)(x=2,y=3$

$x+3y=11$
$x=color(green)(11-3y$ ....equation $(1)$

$x+4y=14$ ...equation $(2)$

Substituting equation $(1)$ in equation $(2)$ to find $y$

$x+4y=14$

$color(green)(11-3y+4y=14$

$11-3y+4y=14$

$11+y=14$

$color(green)(y=3$

Substituting the value of $y$ in equation $(1)$ to find $x$

$x=11 -3y$

$x=11-3*3$

$color(green)(x=2$

How do you solve x+3y=11 x+3y=11 and x+4y=14x+4y=14?