Question

How do you solve `-x/4 = (2x)/3`?

Answer 1

`0=x`

Explanation:

`-x/4=(2x)/3|+x/4`
`0=(2x)/3+x/4`
`0=(11x)/12|*12/11`
`0=x`

Answer 2

See a solution process below:

Explanation:

First, multiply each side of the equation by `color(red)(12)` to eliminate the fractions while keeping the equation balanced:

`color(red)(12) xx -x/4 = color(red)(12) xx (2x)/3`

`cancel(color(red)(12))color(red)(3) xx -x/color(red)(cancel(color(black)(4))) = cancel(color(red)(12))color(red)(4) xx (2x)/color(red)(cancel(color(black)(3)))`

`color(red)(3) xx -x = color(red)(4) xx 2x`

`-3x = 8x`

Next, add `color(red)(3x)` to each side of the equation to isolate the `x` term while keeping the equation balanced:

`-3x + color(red)(3x) = 8x + color(red)(3x)`

`0 = (8 + color(red)(3))x`

`0 = 11x`

Now, divide each side of the equation by `color(red)(11)` to solve for `x` while keeping the equation balanced:

`0/color(red)(11) = (11x)/color(red)(11)`

`0 = (color(red)(cancel(color(black)(11)))x)/cancel(color(red)(11))`

`0 = x`

`x = 0`