How do you solve $x^(4/3)+9=25$ ?

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Answer 1 · 2016-01-09T14:18:45

$x=8$

Firstly, we rearrange the equation so that there will only be equation with one unknown on one side while integer on the other side.

So,
$x^(4/3)+9=25$

$x^(4/3)=25-9$

$x^(4/3)=16$

To eliminate the power on unknown $x$ , we need to whether add to the power of or to the power root of on both side of the equation. For example;

$x^(4/3)=16$ also equals to $root(3)(x)^(4)=16$

Let say we want to eliminate the power root of $3$ on $x$ , we must add to the power of $3$ onto both side of equation;

$x^(4/3)=16$
Add to the power of $3$ on both side of equation;

$x^((4/3)(3))=16^3$

$x^(4)=4096$

Let say then we want to eliminate the power of $4$ on $x$ , we must add to the power root of $4$ onto both side of equation;

$x^(4)=4096$
Add to the power root of $4$ on both side of equation;

$x^((4)(1/4))=4096^(1/4)$

$x=8$

How do you solve x^(4/3)+9=25x^(4/3)+9=25?