How do you solve $x/4 - 4/x=0$ ?

Question

2342 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-25T04:54:33

Work backwards combine like terms and remove the fractions

The order of operations is PEMDAS in reverse it is PESADM

Start by removing the parenthesis a / divided symbol acts as a parenthesis so remove the division symbols like this

$4x xx (x)/4 - 4x xx (4)/x = 4x xx 0$

Dividing out the common terms gives

$x^2 - 16 = 0$

Work backwards by subtracting 16 from both sides

$x^2 - 16 +16 = 0 +16$

This gives

$x^2 = 16$

Taking the square root of both sides gives

$sqrt x^2 = sqrt 16$

Which gives and imaginary number

$x = (+/- )4$

Answer 2 · 2018-07-25T08:01:16

Add $4/x$ to both sides

$=> x/4=4/x$

Cross multiply

$x^2=16$

Square root both sides

$x= \pm4$

How do you solve x/4 - 4/x=0x/4 - 4/x=0?