How do you solve (x-6)^(1/2) +4=0(x−6)12+4=0 and find any extraneous solutions?

2 Answers
G_Ozdilek
Apr 12, 2017

x=-10x=−10

Explanation:

Get rid of square root first:
((x-6)^0.5)^2+4^2=0((x−6)0.5)2+42=0
(x-6)=-16(x−6)=−16
x=-16+6=-10x=−16+6=−10

This is the solution of your equation. x=-10x=−10

Barney V.
Apr 12, 2017

color(blue)(x=22x=22

Explanation:

(x-6)^(1/2)+4=0(x−6)12+4=0

:.(x-6)^(1/2)=-4

:.sqrt(x-6)=-4

square both sides

:.(sqrt(x-6))^2=(-4)^2

:.sqrt(x-6) xx sqrt(x-6)=x-6

:.x-6=16

:.x=16+6

:.color(blue)(x=22

sustitute x=22

:.sqrt(22-6)+4=0

:.+-sqrt(16)+4=0

:.+-4+4=0

:.color(blue)(-4+4=0
4+4= extraneous solution

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