How do you solve $x + y = 14$ $x + y = 14$ and $- x + y = 16$ $-x + y = 16$ ?

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Answer 1 · 2015-08-02T14:08:09

The solution for the system of equations is
$x = - 1, y = 15$ $color(blue)(x=-1,y=15$

$x + y = 14$ $color(blue)(x)+y=14$ .......equation $(1)$ $(1)$
$- x + y = 16$ $color(blue)(−x)+y=16$ ...equation $(2)$ $(2)$

Upon adding the equations $x$ $color(blue)(x$ gets eliminated
$cancelcolor(blue)(x)+y=14$
$cancelcolor(blue)(−x)+y=16$

$2y=30$
$color(blue)(y=15$

Substituting the value of $y$ in equation $(1)$ to find $x$
$x+y=14$

$x=14-15$
$color(blue)(x=-1$

How do you solve x + y = 14x+y=14x + y = 14 and -x + y = 16−x+y=16-x + y = 16?