How do you solve $x - y = 16$ $x - y = 16$ and $2 x + y = 2$ $2x + y = 2$ ?

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Answer 1 · 2015-08-02T14:11:35

The solution for the system of equations is
$x = 6, y = - 10$ $color(blue)(x=6, y=-10$

$x - y = 16$ $x−color(blue)(y)=16$ .....equation $(1)$ $(1)$
$2 x + y = 2$ $2x+color(blue)(y)=2$ .....equation $(2)$ $(2)$

Upon adding the two equations $y$ $color(blue)(y$ gets eliminated.

$x−cancelcolor(blue)(y)=16$
$2x+cancelcolor(blue)(y)=2$

$3x=18$
$color(blue)(x=6$

Now, we substitute the value of $x$ to find $y$
From equation $1$ :

$x−y=16$

$x−16=y$

$y=6-16$
$color(blue)(y=-10$

How do you solve x - y = 16x−y=16x - y = 16 and 2x + y = 22x+y=22x + y = 2?