How do you solve $x - y = 2$ $x-y=2$ and $3 x + y = - 10$ $3x+y=-10$ ?

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Answer 1 · 2016-06-21T13:51:51

By substitution.

$x = 2 + y$ $x = 2 + y$

$3 (2 + y) + y = - 10$ $3(2 + y) + y = -10$

$6 + 3 y + y = - 10$ $6 + 3y + y = -10$

$4 y = - 16$ $4y = -16$

$y = - 4$ $y = -4$

$x - (- 4) = 2$ $x - (-4) = 2$

$x = 2 - 4$ $x = 2 - 4$

$x = - 2$ $x = -2$

Thus, the solution set is ${- 2, - 4}$ ${-2, -4}$ .

Hopefully this helps!

How do you solve x-y=2x−y=2x-y=2 and 3x+y=-103x+y=−103x+y=-10?