Question

How do you solve `(y-1)/(y-2)=-y/(y+1)`?

Answer 1

Refer to explanation

Explanation:

We multiply both sides with `(y-2)*(y+1)` hence we get

#(y-1)/(y-2)=-y/(y+1)=>(y+1)*(y-1)=-(y-2)*y=>y^2-1=-y^2+2y=> 2y^2+2y-1=0=>y_1=-1/2-sqrt3/2 or y_2=-1/2+sqrt3/2#