How do you solve $y + 2 x = 3$ $y + 2x =3$ and $4 x = 2 - 2 y$ $4x = 2 -2y$ ?

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How do you solve $y + 2 x = 3$ $y + 2x =3$ and $4 x = 2 - 2 y$ $4x = 2 -2y$ ?

1 Answer

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Answer 1 · 2015-08-03T21:26:18

Your system has no solutions.

Explanation:

You can write your system as:
${2 x + y = 3$ ${2x+y=3$
${4 x + 2 y = 2$ ${4x+2y=2$
In this way you can see that, apart for the terms after the $=$ $=$ sign, the second equation is equal to the first one multiplied by $2$ $2$ .
This implies that your two equations represent two parallel line with no points (and solutions) in common.
Graphically:
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How do you solve $y + 2 x = 3$ $y + 2x =3$ and $4 x = 2 - 2 y$ $4x = 2 -2y$ ?

1 Answer

Explanation:

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How do you solve y + 2x =3y+2x=3y + 2x =3 and 4x = 2 -2y4x=2−2y4x = 2 -2y?

1 Answer

Explanation:

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How do you solve $y + 2 x = 3$ $y + 2x =3$ and $4 x = 2 - 2 y$ $4x = 2 -2y$ ?