How do you solve y = 2x and 3x - 2y = -2?

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How do you solve y = 2x and 3x - 2y = -2?

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Answer 1 · 2018-03-19T11:45:18

$x = 2, y = 4$ $x=2,y=4$

Explanation:

It's a system of 2 equations with 2 unknown numbers. Let's first put all x and y on the left.
$y - 2 x = 0, 3 x - 2 y = - 2$ $y-2x=0, 3x-2y=-2$
Now you have to eliminate y in the second equation, using the first.
$y - 2 x = 0, 3 x - 2 y + 2 \cdot (y - 2 x) = - 2 + 2 \cdot 0$ $y-2x=0, 3x-2y+2*(y-2x)=-2+2*0$
We have :
$y - 2 x = 0, - x = - 2 \Leftrightarrow x = 2$ $y-2x=0, -x=-2 <=> x=2$
Finally replace x by its value.
$y - 2 \cdot 2 = 0 \Leftrightarrow y = 4$ $y-2*2=0 <=> y=4$

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How do you solve y = 2x and 3x - 2y = -2?

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