Question

How do you solve `(y+3)/3 =( 3y-5)/2`?

Answer 1

`color(blue)(y=3`

Explanation:

`(y+3)/color(blue)(3) =(3y-5)/color(blue)(2`

**Cross multiplying **

`(y+3) * color(blue)(2) =(3y-5) *color(blue)(3`

`2y +6 = 9y -15`

`6 +15 = 9y - 2y`

`21 = 7y`

`y = 21/7`
`color(blue)(y=3`