How do you solve y + 3x = 11 and 2y - x = 2?

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How do you solve y + 3x = 11 and 2y - x = 2?

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Answer 1 · 2015-09-05T16:44:34

$x = \frac{20}{7}$ $x = (20)/(7)$
$y = \frac{17}{7}$ $y = 17/7$

Explanation:

y + 3x = 11 --------------(1)
2y - x = 2 --------------(2)

Solve the 1st equation for y
y = 11 -3x --------------(3)

Substitute the value of y = 11 - 3x in equation (2)

2(11 - 3x) - x = 2
22 - 6x - x = 2
-7x = 2 -22
$x = \frac{- 20}{- 7}$ $x = (-20)/(-7)$
$x = \frac{20}{7}$ $x = (20)/(7)$

Substitute the value of x in equation (3)
$y = 11 - 3 (\frac{20}{7})$ $y = 11 - 3(20/7)$
$y = 11 - (\frac{60}{7})$ $y = 11 - (60/7)$
$y = \frac{77 - 60}{7} = \frac{17}{7}$ $y = (77 -60)/7=17/7$
$y = \frac{17}{7}$ $y = 17/7$

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How do you solve y + 3x = 11 and 2y - x = 2?

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