How do you solve $y + 3 x = 5$ $y + 3x = 5$ and $y = 2 x + 5$ $y = 2x + 5$ ?

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Answer 1 · 2015-08-02T23:01:32

$x = 0, y = 5$ $color(red)( x=0,y=5)$

One way is to use the method of elimination.

Step 1. Enter the equations.

[1] $y + 3 x = 5$ $y+3x=5$
[2] $y = 2 x + 5$ $y=2x+5$

Step2. Prepare the equations.

[3] $3 x + y = 5$ $3x+y=5$
[4] $2 x - y = - 5$ $2x-y = -5$

Step 3. Add the equations.**

[5] $5 x = 0$ $5x=0$

Step 4. Solve for $x$ $x$ .

[6] $x = 0$ $x=0$

Step 5. Substitute Equation 6 in Equation 1.

$y + 3 x = 5$ $y+3x=5$

$y + 3 (0) = 5$ $y+3(0) = 5$

$y + 0 = 5$ $y+0 = 5$

$y = 5$ $y=5$

Solution: $x = 0, y = 5$ $x=0,y=5$

Check: Substitute the values of $x$ $x$ and $y$ $y$ in Equation 2.

$y = 2 x + 5$ $y = 2x+5$
$5 = 2 (0) + 5$ $5 = 2(0) +5$
$5 = 0 + 5$ $5 = 0+5$
$5 = 5$ $5=5$

How do you solve y + 3x = 5y+3x=5y + 3x = 5 and y = 2x + 5y=2x+5y = 2x + 5?