How do you solve $y = - 3 x + 6$ $y = -3x + 6$ and $3 x - y = 6$ $3x-y = 6$ ?

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Answer 1 · 2015-08-04T05:41:07

The solution for the system of equations is
$x = 2, y = 0$ $color(blue)(x=2,y=0$

$y = - 3 x + 6$ $y=color(blue)(−3x+6$ .....equation $(1)$ $(1)$

$3 x - y = 6$ $3x−y=6$ .........equation $(2)$ $(2)$

Solving through substitution:
Substituting equation $1$ $1$ in equation $2$ $2$

$3 x - y = 6$ $3x−y=6$

$3 x - (- 3 x + 6) = 6$ $3x-color(blue)((−3x+6))=6$

$3 x + 3 x - 6 = 6$ $3x + 3x -6=6$

$6 x = 6 + 6$ $6x =6+6$

$x = 2$ $color(blue)(x=2$

Substituting $x$ $x$ in equation $1$ $1$ to find $y$ $y$
$y = - 3 x + 6$ $y=−3x+6$

$y = - 3 \cdot 2 + 6$ $y=−3*2+6$

$y = - 6 + 6$ $y=−6+6$

$y = 0$ $color(blue)(y=0$

How do you solve y=−3x+6 y = -3x + 6 and 3x−y=63x-y = 6?