How do you solve $y = -x+2$ and $y= 3x-2$ ?

Question

4018 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-08-10T09:41:42

The answer is $x = 1$ ; $y = 1$

Since

${(y = -x + 2), (y = 3x - 2) :}$

We shall have

$-x +2 = 3x - 2$

$-x +2 - 3x + 2 = 0$

$- 4x + 4 = 0$

$- 4x = -4 implies x = (-4)/(-4) = 1$

Substitute $x = 1$ in the first equation to get

$y = -1 + 2$

$y = 1$

How do you solve y = -x+2y = -x+2 and y= 3x-2y= 3x-2?