How do you use FOIL to multiply $(2 x - 5) (3 x + 6)$ $(2x-5)(3x+6)$ ?

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Answer 1 · 2018-05-25T13:02:38

$6 x^{2} - 3 x - 30$ $6x^2-3x-30$

Given: $(2 x - 5) (3 x + 6)$ $(2x-5)(3x+6)$ .

$FOIL$ $"FOIL"$ states that for a product of $(a + b) (c + d)$ $(a+b)(c+d)$ , the answer is: $a c + a d + b c + b d$ $ac+ad+bc+bd$ .

So, here we get:

$= 2 x \cdot 3 x + 2 x \cdot 6 - 5 \cdot 3 x - 5 \cdot 6$ $=2x*3x+2x*6-5*3x-5*6$

$= 6 x^{2} + 12 x - 15 x - 30$ $=6x^2+12x-15x-30$

$= 6 x^{2} - 3 x - 30$ $=6x^2-3x-30$

How do you use FOIL to multiply (2x-5)(3x+6)(2x−5)(3x+6)(2x-5)(3x+6)?