How do you use half angle formula to find $sin ((11pi)/12)$ ?

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Answer 1 · 2015-05-16T02:45:32

On the trig unit circle, $sin (11pi)/12 = sin (pi/12)$

$2sin^2 (pi/12) = 1 - cos (pi/6)$ = $1 - (sqr3)/2 = 0.134$

$sin^2 (pi/12) = 0.067 -> sin (pi/12) = sin ((11pi)/12) = 0.26.$

How do you use half angle formula to find sin ((11pi)/12)sin ((11pi)/12)?