How do you use substitution or elimination to solve the system of equations? 2x-3y-z=0, 3x+2y+2z=2, and x+5y+3z=2

1 Answer
Dec 6, 2017

The given system of eqns. has infinitely many solutions.

Explanation:

Name the given eqns. 2x-3y-z=0..............................<<1>>.

3x+2y+2z=2...........................................................<<2>>.

x+5y+3z=2..............................................................<<3>>.

Observe that, adding <<1>> and <<3>>," we get "<<2>>.

Therefore, the given system of eqns. has infinitely many solns.