How do you use the quadratic formula to solve $-2x^2+3x+4=1$ ?

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Answer 1 · 2018-06-09T09:37:02

$color(gray)(x = (3 - sqrt33) / 4, (3 + sqrt33) / 3$

$-2x^2 + 3x + 4 - 1 = 0$

$-2x^2 + 3x + 3 = 0$

$a = -2, b = 3, c = 3$

$"Quadratic formula is " x = (-b +- sqrt(b^2 - 4ac)) / (2a)$

$x = (-3 +- sqrt(9 + 24)) / -4$

$color(gray)(x = (3 - sqrt33) / 4, (3 + sqrt33) / 3$

How do you use the quadratic formula to solve -2x^2+3x+4=1-2x^2+3x+4=1?