How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ?
1 Answer
Sep 8, 2014
#y'=2/3*1/x^(1/3)-1/6*1/x^(5/6)# Solution:
#y=(x−sqrtx)/x^(1/3)#
#y=x/x^(1/3)-x^(1/2)/x^(1/3)#
#y=x^(2/3)-x^(1/6)# differentiating with respect to
#x# ,
#y'=2/3x^(2/3-1)-1/6x^(1/6-1)#
#y'=2/3x^(-1/3)-1/6x^(-5/6)#
#y'=2/3*1/x^(1/3)-1/6*1/x^(5/6)#