How do you write #14^(2/5)# in radical notation? Algebra Exponents and Exponential Functions Fractional Exponents 1 Answer Ratnaker Mehta Sep 11, 2016 #14^(2/5)=(14^2)^(1/5)=196^(1/5)=5^(th) "root of "196# Now, #5^(th) "root of a number"# is , in radical sign, written as #root(5)("the number)"#. Hence, #14^(2/5)=root(5)(196)#. Answer link Related questions What are Fractional Exponents? How do you convert radical expressions to fractional exponents? How do you simplify fractional exponents? How do you evaluate fractional exponents? Why are fractional exponents roots? How do you simplify #(x^{\frac{1}{2}} y^{-\frac{2}{3}})(x^2 y^{\frac{1}{3}})#? How do you simplify #((3x)/(y^(1/3)))^3# without any fractions in the answer? How do you simplify #\frac{a^{-2}b^{-3}}{c^{-1}}# without any negative or fractional exponents... How do you evaluate #(16^{\frac{1}{2}})^3#? What is #5^0#? See all questions in Fractional Exponents Impact of this question 2141 views around the world You can reuse this answer Creative Commons License