How do you write $(4x^(1/3)y^(5/3))/(16x^(4/3)y^(2/3))$ in radical form?

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Answer 1 · 2018-04-28T08:36:07

$y/(4x)$

$(4x^(1/3)y^(5/3))/(16x^(4/3)y^(2/3))$

Separate the fraction into like-terms,

$4/16*(x^(1/3))/(x^(4/3))*(y^(5/3))/(y^(2/3))$

Apply division rule,

$1/4*x^(1/3-4/3)*y^(5/3-2/3)$

Simplify,

$1/4*x^-1*y$

Combine,

$y/(4x)$

How do you write (4x^(1/3)y^(5/3))/(16x^(4/3)y^(2/3))(4x^(1/3)y^(5/3))/(16x^(4/3)y^(2/3)) in radical form?