How do you write $7^{\frac{2}{3}}$ $7^(2/3)$ in radical form?

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Answer 1 · 2015-05-28T17:20:30

$7^{\frac{2}{3}}$ $7^(2/3)$ in radical form could be written as

${(\sqrt[3]{7})}^{2}$ $(root(3)(7))^2$
or
$\sqrt[3]{7^{2}}$ $root(3)(7^2)$
or
$\sqrt[3]{49}$ $root(3)(49)$

How do you write 7^(2/3)7237^(2/3) in radical form?