How do you write $(9y^6) ^(3/2)$ as a radical form?

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Answer 1 · 2016-08-02T12:38:08

$(9y^6) ^(3/2)$ can be written as $sqrt((9y^6))^3$
It simplifies to $27y^9$

One of the laws of indices states that $x^(p/q) = rootq(x)^p$

(The denominator or the index is the root and the numerator is the power)

$(9y^6) ^(3/2)$ can be written as $sqrt((9y^6))^3$

This can be simplified:
$=(3y^3)^3$

= $27y^9$

How do you write (9y^6) ^(3/2)(9y^6) ^(3/2) as a radical form?