How do you write $a^{- 1.6}$ $a^-1.6$ in radical form?

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Answer 1 · 2016-09-02T00:08:38

$\frac{1}{\sqrt[5]{a^{8}}}$ $1/root5(a^8)$

$a^{- 1.6} = a^{- \frac{8}{5}}$ $a^-1.6 = a^(-8/5)$

= $\frac{1}{a^{\frac{8}{5}}}$ $1/a^(8/5)$

= $\frac{1}{\sqrt[5]{a^{8}}}$ $1/root5(a^8)$

How do you write a^-1.6a−1.6a^-1.6 in radical form?