How do you write $(a^2b^2)^(1/9)$ in radical form?

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Answer 1 · 2018-07-14T13:38:46

$root9 (a^2b^2)$

$a^(1/3 = root 3 a)$

$:.(a^2b^2)^(1/9)=root 9 (a^2b^2)$

Answer 2 · 2018-07-14T13:39:29

Use this rule: $x^(1/color(red)(n)) = root(color(red)(n))(x)$

$(a^2b^2)^(1/color(red)(9)) = root(color(red)(9))(a^2b^2)$

How do you write (a^2b^2)^(1/9)(a^2b^2)^(1/9) in radical form?