How do you write $\sqrt[5]{b^{2}}$ $root5(b^2)$ as an exponential expression?

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Answer 1 · 2018-04-30T10:00:37

$b^{\frac{2}{5}}$ $b^(2/5)$

Since $\sqrt[n]{a} = a^{\frac{1}{n}},$ $root(n)a = a^(1/n) ,$

$\sqrt[5]{b^{2}} = b^{\frac{2}{5}}$ $root(5)(b^2) = b^(2/5)$

How do you write 5√b2 root5(b^2) as an exponential expression?