How do you write $root6(7/3 p^2 q)$ as an exponenetial form?

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Answer 1 · 2016-01-18T12:19:01

= $(7^(1/6) p^ (1/3) q^(1/6))/3^(1/6)$

It is the 6th root of the given expression inside the radical sign. Hence write:

$(7^(1/6) p^(2/6) q^(1/6) )/3^(1/6)$

= $(7^(1/6) p^ (1/3) q^(1/6))/3^(1/6)$

How do you write root6(7/3 p^2 q)root6(7/3 p^2 q) as an exponenetial form?