How do you write $\sqrt{x}$ $sqrtx$ as an exponential form?

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How do you write $\sqrt{x}$ $sqrtx$ as an exponential form?

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Answer 1 · 2016-01-14T20:37:29

I found $x^{\frac{1}{2}}$ $x^(1/2)$

Explanation:

You can change a root into a fractional exponent such as:
$\sqrt[n]{x^{m}} = x^{\frac{m}{n}}$ $rootn(x^m)=x^(m/n)$
So in your case:
$\sqrt{x} = \sqrt[2]{x^{1}} = x^{\frac{1}{2}}$ $sqrt(x)=root2(x^1)=x^(1/2)$

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How do you write $\sqrt{x}$ $sqrtx$ as an exponential form?

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