How do you write the expression $\frac{{tan 325}^{\circ} - {tan 86}^{\circ}}{1 + {tan 325}^{\circ} {tan 86}^{\circ}}$ $(tan325^circ-tan86^circ)/(1+tan325^circtan86^circ)$ as the sine, cosine, or tangent of an angle?

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How do you write the expression $\frac{{tan 325}^{\circ} - {tan 86}^{\circ}}{1 + {tan 325}^{\circ} {tan 86}^{\circ}}$ $(tan325^circ-tan86^circ)/(1+tan325^circtan86^circ)$ as the sine, cosine, or tangent of an angle?

1 Answer

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Answer 1 · 2017-01-16T03:40:15

tan (325 - 86) = tan 239

Explanation:

Apply the trig identity:
$tan (a - b) = \frac{tan a - tan b}{1 + tan a . tan b}$ $tan (a - b) = (tan a - tan b)/( 1 + tan a.tan b)$
$\frac{tan 325 - tan 86}{1 + tan 325 . tan 86} = tan (325 - 86) = tan 239$ $(tan 325 - tan 86)/(1 + tan 325.tan 86) = tan (325 - 86) = tan 239$

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How do you write the expression $\frac{{tan 325}^{\circ} - {tan 86}^{\circ}}{1 + {tan 325}^{\circ} {tan 86}^{\circ}}$ $(tan325^circ-tan86^circ)/(1+tan325^circtan86^circ)$ as the sine, cosine, or tangent of an angle?

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Explanation:

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How do you write the expression tan325∘−tan86∘1+tan325∘tan86∘(tan325^circ-tan86^circ)/(1+tan325^circtan86^circ) as the sine, cosine, or tangent of an angle?

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Explanation:

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How do you write the expression $\frac{{tan 325}^{\circ} - {tan 86}^{\circ}}{1 + {tan 325}^{\circ} {tan 86}^{\circ}}$ $(tan325^circ-tan86^circ)/(1+tan325^circtan86^circ)$ as the sine, cosine, or tangent of an angle?