How do you write $x^{\frac{9}{4}}$ $x^(9/4)$ as a radical form?

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How do you write $x^{\frac{9}{4}}$ $x^(9/4)$ as a radical form?

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Answer 1 · 2016-02-10T05:47:38

$x^{\frac{9}{4}}$ $x^(9/4)$ is $\sqrt[4]{x^{9}}$ $root(4)(x^9)$ .

Explanation:

The numerator denotes the actual exponent, like $x^{2}$ $x^2$ . Therefore, we so far have $x^{9}$ $x^9$ . Now the denominator denotes the numbered root of $x$ $x$ . So, $x^{\frac{1}{4}}$ $x^(1/4)$ would be $\sqrt[4]{x}$ $root(4)(x)$ . Therefore, $x^{\frac{9}{4}}$ $x^(9/4)$ is $\sqrt[4]{x^{9}}$ $root(4)(x^9)$ .

And we are done.

Answer 2 · 2016-02-13T08:46:05

$x^{\frac{9}{4}} = \sqrt[4]{x^{9}}$ $x^(9/4)=root(4)(x^9)$

Explanation:

Remember the formula $x^{\frac{a}{b}} = \sqrt[b]{x^{a}}$ $color(blue)(x^(a/b)=root(b)(x^a)$

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