How to solve for y in $5x-y=33$ and $7x+y=51$ ?

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Answer 1 · 2015-04-08T01:41:44

$y=5x-33$ and $y=-7x+51$ .

First Equation:

$5x-y=33$

Subtract $5x$ from both sides.

$-y=33-5x$

Multiply both sides by $-1$ .

$y=-33+5x$

Rearrange.

$y=5x-33$

Second Equation:

$7x+y=51$

Substitute the $y$ from the first equation

$7x+(5x-33)=51->12x-33=51$

Add $33$ to both sides, and then divide by $12$

$12x=84->x=7$

Now put this into the equation for $y$

$y=5x-33->y=5*7-33=35-33->y=2$

Answer : $x=7,y=2$

How to solve for y in 5x-y=335x-y=33 and 7x+y=517x+y=51?