How would you simplify $\sqrt{6} \cdot \sqrt{2}$ $sqrt6 * sqrt2$ ?

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Answer 1 · 2016-04-27T11:20:41

$2 \sqrt{3}$ $2sqrt3$

We can write the numbers as $\sqrt{2 \times 3} \times \sqrt{2}$ $sqrt(2xx3)xxsqrt2$

$= \sqrt{2} \times \sqrt{3} \times \sqrt{2}$ $=sqrt2 xx sqrt3 xx sqrt2$

Here, $\sqrt{2} \times \sqrt{2} = \sqrt{2 \times 2} = 2$ $color(red)( sqrt2xxsqrt2=sqrt(2xx2)=2)$

$= 2 \times \sqrt{3}$ $=2xxsqrt3$

$= 2 \sqrt{3}$ $=2sqrt3$

How would you simplify √6⋅√2sqrt6 * sqrt2?