If the pH is 14.75, what is $[OH^-]$ ?

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Answer 1 · 2016-06-15T07:32:40

In aqueous solution under standard conditions, $pH+pOH=14$

Given the above, $pOH$ $=$ $-0.75$ .

Thus $[HO^-]$ $=$ $10^(-(-0.75))$ $=$ $10^(+0.75)$ $=$ $5.62*mol*L^-1$ .

If the pH is 14.75, what is [OH^-][OH^-]?