Simplify this function of Double Angles?

Question

#(sin6x)/(sin2x) - (cos6x)/(cos2x)#

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Answer 1 · 2017-04-02T17:54:33

2

the given expression can be added as #(sin 6x cos 2x -sin 2x cos 6x)/(sin 2x cos 2x)#

The expression in the numerator is equivalent to sin (6x-2x)= sin 4x= 2 sin 2x cos 2x

the given expression is thus reduced to #(2 sin 2x cos 2x )/ (sin 2x cos 2x)# = 2