What are the intercepts of $-7y=3y-2(x-9) -x^2$ ?

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Answer 1 · 2018-06-06T00:28:28

$x=-10+-sqrt19$

$y=-9/5$

To find the y-intercepts set x=0 and solve for y:

$-7y=3y-2(x-9) -x^2$

$-7y=3y-2(0-9) -0^2$

$-7y=3y-2(-9)$

$-7y=3y+18$

$-10y=18$

$y=-9/5$

To find the x-intercept(s) if they exist set y=0 and solve for x:

$-7y=3y-2(x-9) -x^2$

$-7(0)=3(0)-2(x-9) -x^2$

$0=-2(x-9) -x^2$

$0=-x^2-2(x-9)$

$0=-x^2-2x+18$

$0=x^2+2x-18$

You will need to complete the square or use the quadratic equation to find these roots:

$x=-10+-sqrt19$

graph{-7y=3y-2(x-9) -x^2 [-20.58, 19.42, -4.8, 15.2]}

What are the intercepts of -7y=3y-2(x-9) -x^2-7y=3y-2(x-9) -x^2?